# Commission Regulation (EC) No 152/2009 of 27 January 2009 laying down the methods of sampling and analysis for the official control of feed (Text with EEA relevance), Division 6: Calculation of results

Extent: E+W+S+N.I.

Using the attached table, establish the amount of lactose in mg which corresponds to the difference between the results of the two titrations, expressed in ml of sodium thiosulphate 0,1 mol/litre.
Express the result of anhydrous lactose as a percentage of the sample.

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Source: https://www.legislation.gov.uk/eur/2009/152/annex/III/division/K/division/6 (the official version)
Page: https://openlegislation.uk/eu-regulation-2009-152/annex-III/division-K/division-6
Contains public sector information licensed under the Open Government Licence v3.0. Source: legislation.gov.uk, The National Archives.