Paragraph 6 EXPRESSION OF RESULTS

$$\text{Percentage of material passing sieve of 0.630 mm apertures}=\left(50-\mathrm{M}1\right)\times 2$$ $$\text{Percentage of material passing sieve of 0.160 mm apertures}=\mathrm{[50}-\left(\mathrm{M}1+\mathrm{M}2\right)\mathrm{]}\times 2$$

where:

• M₁ = mass in g of residue on the sieve with 0.630 mm apertures

• M₂ = mass in g of residue on the sieve with 0.160 mm apertures

• The results are to be rounded up to the nearest unit.