Paragraph 6 EXPRESSION OF RESULTS

Express the result of the analysis as the percentage of chlorine contained in the sample as received for analysis.

Calculate the percentage of chlorine (Cl) content from the formula:

$$\mathrm{Cl\%}=\genfrac{}{}{0.1ex}{}{0.03545\times \mathrm{T}\times \left(\mathrm{V}5-\mathrm{V}4\right)\times 100}{\mathrm{m}}$$

where:

• T is the molarity of silver nitrate solution used;

• V₄ is the result, in ml, of the blank test (5.2);

• V₅ is the value, in ml, of V_eq corresponding to the determination (5.4);

• m is the mass, in grams, of the test portion.

$$\mathrm{V}\mathrm{eq}=4.9+0.1\times \genfrac{}{}{0.1ex}{}{37}{37+49}=4.943$$