# Fertilisers (Sampling and Analysis) Regulations (Northern Ireland) 1996, Paragraph 10: EXPRESSION OF RESULTS


The percentage of boron in fertiliser is given by:
B%=(X1-X0)×F×V10×a×M where:
B% is the percentage of boron in the fertiliser;
x1 is the volume, in ml, of the 0.025 M sodium hydroxide solution (4.4);
xo is the volume, in ml, of the 0.025 M sodium hydroxide solution M (4.4);
F is the boron (B) value, in mg/ml, of the 0.025 M sodium hydroxide solution (4.4);
V is the volume, in ml, of the extract solution obtained in accordance with Method 26a or 26b;
a is the volume, in ml, of the aliquot (7.1) taken from the extract solution (6.1);
M is the mass, in grams, of the test sample taken in accordance with Method 26a or 26b.

---
Source: https://www.legislation.gov.uk/nisr/1996/513/schedule/2/part/I/chapter/26e./paragraph/10 (the official version)
Page: https://openlegislation.uk/fertilisers-sampling-and-analysis-regulations-northern-ireland-1996/schedule-2/part-I/chapter-26e./paragraph-10
Contains public sector information licensed under the Open Government Licence v3.0. Source: legislation.gov.uk, The National Archives.