# Fertilisers (Sampling and Analysis) Regulations (Northern Ireland) 1996, Paragraph 8: EXPRESSION OF RESULTS


1 mg of Co (C10H6ONO)3.2H2O precipitate corresponds to 0.096381 mg Co.
The percentage of cobalt (Co) in the fertiliser is given by:
V×DCo(%)=X×0.0096381×———V×Da×M where:
X is the mass in mg of the precipitate;
V is the volume in ml of the extract solution obtained in accordance with Method 26a or Method 26b;
a is the volume in ml of the aliquot taken from the last dilution;
D is the dilution factor of this aliquot;
M is the mass in g of the test sample.

---
Source: https://www.legislation.gov.uk/nisr/1996/513/schedule/2/part/I/chapter/26f./paragraph/8 (the official version)
Page: https://openlegislation.uk/fertilisers-sampling-and-analysis-regulations-northern-ireland-1996/schedule-2/part-I/chapter-26f./paragraph-8
Contains public sector information licensed under the Open Government Licence v3.0. Source: legislation.gov.uk, The National Archives.