Paragraph 10 EXPRESSION OF RESULTS

The percentage of boron in fertiliser is given by:

B% = \frac{(X 1 - X 0) \times F \times V}{10 \times a \times M}

where:

B% is the percentage of boron in the fertiliser;
x₁ is the volume, in ml, of the 0.025 M sodium hydroxide solution (4.4);
x_o is the volume, in ml, of the 0.025 M sodium hydroxide solution M (4.4);
F is the boron (B) value, in mg/ml, of the 0.025 M sodium hydroxide solution (4.4);
V is the volume, in ml, of the extract solution obtained in accordance with Method 26a or 26b;
a is the volume, in ml, of the aliquot (7.1) taken from the extract solution (6.1);
M is the mass, in grams, of the test sample taken in accordance with Method 26a or 26b.