Paragraph 8 EXPRESSION OF RESULTS

1 mg of Co (C₁₀H₆ONO)₃.2H₂O precipitate corresponds to 0.096381 mg Co.

The percentage of cobalt (Co) in the fertiliser is given by:

$$\mathrm{V}\times \mathrm{D}\mathrm{Co}\left(\mathrm{\%}\right)=\mathrm{X}\times 0.0096381\times \mathrm{———}\genfrac{}{}{0.1ex}{}{\mathrm{V}\times \mathrm{D}}{\mathrm{a}\times \mathrm{M}}$$

where:

• X is the mass in mg of the precipitate;

• V is the volume in ml of the extract solution obtained in accordance with Method 26a or Method 26b;

• a is the volume in ml of the aliquot taken from the last dilution;

• D is the dilution factor of this aliquot;

• M is the mass in g of the test sample.