Division — 4.5.4 Normalisation of fatty acid moles to 100 % (see formula (2))F1

United Kingdom

moles % P(1,2,3)

$\frac{0,03900 moles P * 100}{0,35821 moles} = 10,887 %$

moles % S(1,2,3)

$\frac{0,01054 moles S * 100}{0,35821 moles} = 2,942 %$

moles % Po(1,2,3)

$\frac{0,00393 moles Po * 100}{0,35821 moles} = 1,097 %$

moles % O(1,2,3)

$\frac{0,26549 moles O * 100}{0,35821 moles} = 74,116 %$

moles % L(1,2,3)

$\frac{0,03566 moles L * 100}{0,35821 moles} = 9,955 %$

moles % Ln(1,2,3)

$\frac{0,00359 moles Ln * 100}{0,35821 moles} = 1,002 %$

Total moles %

100 %

Sum of the saturated and unsaturated fatty acids in the 1,2,3-position of TAGs (see formula (3)):

$moles % SFA = 10,887 % + 2,942 % = 13,829 %$

$moles % UFA = 100,000 % - 13,829 % = 86,171 %$

Annotations

F1: Substituted by Commission Implementing Regulation (EU) No 299/2013 of 26 March 2013 amending Regulation (EEC) No 2568/91 on the characteristics of olive oil and olive-residue oil and on the relevant methods of analysis.